9t+12.5t^2=0

Solution for 9t+12.5t^2=0 equation:

9t+12.5t^2=0

a = 12.5; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·12.5·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*12.5}=\frac{-18}{25}
=-18/25
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*12.5}=\frac{0}{25}
=0
$